Comment: This TM produces 4097 ones in 11798796 steps.
State | on 0 |
on 1 |
on 0 | on 1 | ||||
---|---|---|---|---|---|---|---|---|
Move | Goto | Move | Goto | |||||
A | B1L | A1L | 1 | left | B | 1 | left | A |
B | C1R | D1L | 1 | right | C | 1 | left | D |
C | A1R | C1R | 1 | right | A | 1 | right | C |
D | H1L | E0L | 1 | left | H | 0 | left | E |
E | C1R | B1L | 1 | right | C | 1 | left | B |
The same TM just simple. The same TM with repetitions reduced. The same TM with tape symbol exponents. The same TM as 3-macro machine. Simulation is done as 3-macro machine with pure additive config-TRs. Pushing initial machine. Pushing macro factor 3. Steps BasSteps BasTpos Tape contents 0 0 0 A> 1 1 -1 <B 100 2 2 0 001 C> 100 3 7 -1 001 <E 011 4 10 0 011 C> 011 5 13 -1 011 <A 111 6 16 -4 <B 1112 7 17 -3 001 C> 1112 8 23 3 001 1112 C> 9 26 2 001 1112 <D 110 10 32 -4 001 <D 1103 11 35 -3 011 A> 1103 12 36 -4 011 <A 1103 13 39 -7 <B 111 1103 14 40 -6 001 C> 111 1103 15 43 -3 001 111 C> 1103 16 46 0 001 1112 A> 1102 17 47 -1 001 1112 <A 1102 18 53 -7 001 <A 1112 1102 19 58 -6 111 C> 1112 1102 20 64 0 1113 C> 1102 21 67 3 1114 A> 110 22 68 2 1114 <A 110 23 80 -10 <A 1114 110 24 83 -9 011 C> 1114 110 25 95 3 011 1114 C> 110 26 98 6 011 1115 A> 27 99 5 011 1115 <B 100 28 114 -10 011 <B 1015 100 29 121 -13 <A 111 1015 100 30 124 -12 011 C> 111 1015 100 31 127 -9 011 111 C> 1015 100 32 132 -10 011 111 <A 111 1014 100 33 135 -13 011 <A 1112 1014 100 34 138 -16 <B 1113 1014 100 35 139 -15 001 C> 1113 1014 100 36 148 -6 001 1113 C> 1014 100 37 153 -7 001 1113 <A 111 1013 100 38 162 -16 001 <A 1114 1013 100 39 167 -15 111 C> 1114 1013 100 40 179 -3 1115 C> 1013 100 41 184 -4 1115 <A 111 1012 100 42 199 -19 <A 1116 1012 100 >> Try to prove a PA-CTR with 2 Vars... 0 0 0 <A 1111+V(2) 1014+V(1) [*]* 1 3 1 011 C> 1111+V(2) 1014+V(1) [*]* 2 6+3*V(2) 4+3*V(2) 011 1111+V(2) C> 1014+V(1) [*]* 3 11+3*V(2) 3+3*V(2) 011 1111+V(2) <A 111 1013+V(1) [*]* 4 14+6*V(2) 0 011 <A 1112+V(2) 1013+V(1) [*]* 5 17+6*V(2) -3 <B 1113+V(2) 1013+V(1) [*]* 6 18+6*V(2) -2 001 C> 1113+V(2) 1013+V(1) [*]* 7 27+9*V(2) 7+3*V(2) 001 1113+V(2) C> 1013+V(1) [*]* 8 32+9*V(2) 6+3*V(2) 001 1113+V(2) <A 111 1012+V(1) [*]* 9 41+12*V(2) -3 001 <A 1114+V(2) 1012+V(1) [*]* 10 46+12*V(2) -2 111 C> 1114+V(2) 1012+V(1) [*]* 11 58+15*V(2) 10+3*V(2) 1115+V(2) C> 1012+V(1) [*]* 12 63+15*V(2) 9+3*V(2) 1115+V(2) <A 111 1011+V(1) [*]* 13 78+18*V(2) -6 <A 1116+V(2) 1011+V(1) [*]* << Success! ==> defined new CTR 1 (PA) 43 202 -18 011 C> 1116 1012 100 44 220 0 011 1116 C> 1012 100 45 225 -1 011 1116 <A 111 101 100 46 243 -19 011 <A 1117 101 100 47 246 -22 <B 1118 101 100 48 247 -21 001 C> 1118 101 100 49 271 3 001 1118 C> 101 100 50 276 2 001 1118 <A 111 100 51 300 -22 001 <A 1119 100 52 305 -21 111 C> 1119 100 53 332 6 11110 C> 100 54 337 5 11110 <E 011 55 367 -25 <E 01111 56 368 -24 001 C> 01111 57 371 -25 001 <A 111 01110 58 376 -24 111 C> 111 01110 59 379 -21 1112 C> 01110 60 382 -22 1112 <A 111 0119 61 388 -28 <A 1113 0119 62 391 -27 011 C> 1113 0119 63 400 -18 011 1113 C> 0119 64 403 -19 011 1113 <A 111 0118 65 412 -28 011 <A 1114 0118 66 415 -31 <B 1115 0118 67 416 -30 001 C> 1115 0118 68 431 -15 001 1115 C> 0118 69 434 -16 001 1115 <A 111 0117 70 449 -31 001 <A 1116 0117 >> Try to prove a PA-CTR with 2 Vars... 0 0 0 001 <A 1111+V(2) 0114+V(1) 1 5 1 111 C> 1111+V(2) 0114+V(1) 2 8+3*V(2) 4+3*V(2) 1112+V(2) C> 0114+V(1) 3 11+3*V(2) 3+3*V(2) 1112+V(2) <A 111 0113+V(1) 4 17+6*V(2) -3 <A 1113+V(2) 0113+V(1) 5 20+6*V(2) -2 011 C> 1113+V(2) 0113+V(1) 6 29+9*V(2) 7+3*V(2) 011 1113+V(2) C> 0113+V(1) 7 32+9*V(2) 6+3*V(2) 011 1113+V(2) <A 111 0112+V(1) 8 41+12*V(2) -3 011 <A 1114+V(2) 0112+V(1) 9 44+12*V(2) -6 <B 1115+V(2) 0112+V(1) 10 45+12*V(2) -5 001 C> 1115+V(2) 0112+V(1) 11 60+15*V(2) 10+3*V(2) 001 1115+V(2) C> 0112+V(1) 12 63+15*V(2) 9+3*V(2) 001 1115+V(2) <A 111 0111+V(1) 13 78+18*V(2) -6 001 <A 1116+V(2) 0111+V(1) << Success! ==> defined new CTR 2 (PA) 70 449 -31 001 <A 1116 0117 == Executing PA-CTR 2, V(1)=3, V(2)=5, repcount=2, factor=5/3 96 875 -43 001 <A 11116 011 97 880 -42 111 C> 11116 011 98 928 6 11117 C> 011 99 931 5 11117 <A 111 100 982 -46 <A 11118 101 985 -45 011 C> 11118 102 1039 9 011 11118 C> 103 1042 8 011 11118 <D 110 104 1096 -46 011 <D 11019 105 1101 -45 111 A> 11019 106 1102 -46 111 <A 11019 107 1105 -49 <A 111 11019 108 1108 -48 011 C> 111 11019 109 1111 -45 011 111 C> 11019 110 1114 -42 011 1112 A> 11018 111 1115 -43 011 1112 <A 11018 112 1121 -49 011 <A 1112 11018 113 1124 -52 <B 1113 11018 114 1125 -51 001 C> 1113 11018 115 1134 -42 001 1113 C> 11018 116 1137 -39 001 1114 A> 11017 117 1138 -40 001 1114 <A 11017 118 1150 -52 001 <A 1114 11017 119 1155 -51 111 C> 1114 11017 120 1167 -39 1115 C> 11017 121 1170 -36 1116 A> 11016 >> Try to prove a PA-CTR with 2 Vars... 0 0 0 1111+V(1) A> 1104+V(2) 1 1 -1 1111+V(1) <A 1104+V(2) 2 4+3*V(1) -4+-3*V(1) <A 1111+V(1) 1104+V(2) 3 7+3*V(1) -3+-3*V(1) 011 C> 1111+V(1) 1104+V(2) 4 10+6*V(1) 0 011 1111+V(1) C> 1104+V(2) 5 13+6*V(1) 3 011 1112+V(1) A> 1103+V(2) 6 14+6*V(1) 2 011 1112+V(1) <A 1103+V(2) 7 20+9*V(1) -4+-3*V(1) 011 <A 1112+V(1) 1103+V(2) 8 23+9*V(1) -7+-3*V(1) <B 1113+V(1) 1103+V(2) 9 24+9*V(1) -6+-3*V(1) 001 C> 1113+V(1) 1103+V(2) 10 33+12*V(1) 3 001 1113+V(1) C> 1103+V(2) 11 36+12*V(1) 6 001 1114+V(1) A> 1102+V(2) 12 37+12*V(1) 5 001 1114+V(1) <A 1102+V(2) 13 49+15*V(1) -7+-3*V(1) 001 <A 1114+V(1) 1102+V(2) 14 54+15*V(1) -6+-3*V(1) 111 C> 1114+V(1) 1102+V(2) 15 66+18*V(1) 6 1115+V(1) C> 1102+V(2) 16 69+18*V(1) 9 1116+V(1) A> 1101+V(2) << Success! ==> defined new CTR 3 (PA) 121 1170 -36 1116 A> 11016 == Executing PA-CTR 3, V(1)=5, V(2)=12, repcount=5, factor=5/3 201 2865 9 11131 A> 110 202 2866 8 11131 <A 110 203 2959 -85 <A 11131 110 204 2962 -84 011 C> 11131 110 205 3055 9 011 11131 C> 110 206 3058 12 011 11132 A> 207 3059 11 011 11132 <B 100 208 3155 -85 011 <B 10132 100 209 3162 -88 <A 111 10132 100 >> Try to prove a PPA-CTR with 1 Vars... 0 0 0 1113+V(1) A> 110 1 1 -1 1113+V(1) <A 110 2 10+3*V(1) -10+-3*V(1) <A 1113+V(1) 110 3 13+3*V(1) -9+-3*V(1) 011 C> 1113+V(1) 110 4 22+6*V(1) 0 011 1113+V(1) C> 110 5 25+6*V(1) 3 011 1114+V(1) A> 6 26+6*V(1) 2 011 1114+V(1) <B 100 7 38+9*V(1) -10+-3*V(1) 011 <B 1014+V(1) 100 8 45+9*V(1) -13+-3*V(1) <A 111 1014+V(1) 100 << Success! ==> defined new CTR 4 (PPA) 209 3162 -88 <A 111 10132 100 == Executing PA-CTR 1, V(1)=28, V(2)=0, repcount=10, factor=5/3 339 7992 -148 <A 11151 1012 100 340 7995 -147 011 C> 11151 1012 100 341 8148 6 011 11151 C> 1012 100 342 8153 5 011 11151 <A 111 101 100 343 8306 -148 011 <A 11152 101 100 344 8309 -151 <B 11153 101 100 345 8310 -150 001 C> 11153 101 100 346 8469 9 001 11153 C> 101 100 347 8474 8 001 11153 <A 111 100 348 8633 -151 001 <A 11154 100 349 8638 -150 111 C> 11154 100 350 8800 12 11155 C> 100 351 8805 11 11155 <E 011 352 8970 -154 <E 01156 353 8971 -153 001 C> 01156 354 8974 -154 001 <A 111 01155 >> Try to prove a PPA-CTR with 1 Vars... 0 0 0 <A 1111+V(1) 1012 100 1 3 1 011 C> 1111+V(1) 1012 100 2 6+3*V(1) 4+3*V(1) 011 1111+V(1) C> 1012 100 3 11+3*V(1) 3+3*V(1) 011 1111+V(1) <A 111 101 100 4 14+6*V(1) 0 011 <A 1112+V(1) 101 100 5 17+6*V(1) -3 <B 1113+V(1) 101 100 6 18+6*V(1) -2 001 C> 1113+V(1) 101 100 7 27+9*V(1) 7+3*V(1) 001 1113+V(1) C> 101 100 8 32+9*V(1) 6+3*V(1) 001 1113+V(1) <A 111 100 9 41+12*V(1) -3 001 <A 1114+V(1) 100 10 46+12*V(1) -2 111 C> 1114+V(1) 100 11 58+15*V(1) 10+3*V(1) 1115+V(1) C> 100 12 63+15*V(1) 9+3*V(1) 1115+V(1) <E 011 13 78+18*V(1) -6 <E 0116+V(1) 14 79+18*V(1) -5 001 C> 0116+V(1) 15 82+18*V(1) -6 001 <A 111 0115+V(1) << Success! ==> defined new CTR 5 (PPA) 354 8974 -154 001 <A 111 01155 == Executing PA-CTR 2, V(1)=51, V(2)=0, repcount=18, factor=5/3 588 24148 -262 001 <A 11191 011 589 24153 -261 111 C> 11191 011 590 24426 12 11192 C> 011 591 24429 11 11192 <A 111 592 24705 -265 <A 11193 593 24708 -264 011 C> 11193 594 24987 15 011 11193 C> 595 24990 14 011 11193 <D 110 596 25269 -265 011 <D 11094 597 25274 -264 111 A> 11094 >> Try to prove a PPA-CTR with 1 Vars... 0 0 0 001 <A 1111+V(1) 011 1 5 1 111 C> 1111+V(1) 011 2 8+3*V(1) 4+3*V(1) 1112+V(1) C> 011 3 11+3*V(1) 3+3*V(1) 1112+V(1) <A 111 4 17+6*V(1) -3 <A 1113+V(1) 5 20+6*V(1) -2 011 C> 1113+V(1) 6 29+9*V(1) 7+3*V(1) 011 1113+V(1) C> 7 32+9*V(1) 6+3*V(1) 011 1113+V(1) <D 110 8 41+12*V(1) -3 011 <D 1104+V(1) 9 46+12*V(1) -2 111 A> 1104+V(1) << Success! ==> defined new CTR 6 (PPA) 597 25274 -264 111 A> 11094 == Executing PA-CTR 3, V(1)=0, V(2)=90, repcount=31, factor=5/3 1093 69263 15 111156 A> 110 == Executing PPA-CTR 4 (once), V(1)=153 1101 70685 -457 <A 111 101157 100 == Executing PA-CTR 1, V(1)=153, V(2)=0, repcount=52, factor=5/3 1777 194081 -769 <A 111261 101 100 1778 194084 -768 011 C> 111261 101 100 1779 194867 15 011 111261 C> 101 100 1780 194872 14 011 111261 <A 111 100 1781 195655 -769 011 <A 111262 100 1782 195658 -772 <B 111263 100 1783 195659 -771 001 C> 111263 100 1784 196448 18 001 111263 C> 100 1785 196453 17 001 111263 <E 011 1786 197242 -772 001 <E 011264 1787 197245 -771 011 C> 011264 1788 197248 -772 011 <A 111 011263 1789 197251 -775 <B 1112 011263 1790 197252 -774 001 C> 1112 011263 1791 197258 -768 001 1112 C> 011263 1792 197261 -769 001 1112 <A 111 011262 1793 197267 -775 001 <A 1113 011262 >> Try to prove a PPA-CTR with 1 Vars... 0 0 0 <A 1113+V(1) 101 100 1 3 1 011 C> 1113+V(1) 101 100 2 12+3*V(1) 10+3*V(1) 011 1113+V(1) C> 101 100 3 17+3*V(1) 9+3*V(1) 011 1113+V(1) <A 111 100 4 26+6*V(1) 0 011 <A 1114+V(1) 100 5 29+6*V(1) -3 <B 1115+V(1) 100 6 30+6*V(1) -2 001 C> 1115+V(1) 100 7 45+9*V(1) 13+3*V(1) 001 1115+V(1) C> 100 8 50+9*V(1) 12+3*V(1) 001 1115+V(1) <E 011 9 65+12*V(1) -3 001 <E 0116+V(1) 10 68+12*V(1) -2 011 C> 0116+V(1) 11 71+12*V(1) -3 011 <A 111 0115+V(1) 12 74+12*V(1) -6 <B 1112 0115+V(1) 13 75+12*V(1) -5 001 C> 1112 0115+V(1) 14 81+12*V(1) 1 001 1112 C> 0115+V(1) 15 84+12*V(1) 0 001 1112 <A 111 0114+V(1) 16 90+12*V(1) -6 001 <A 1113 0114+V(1) << Success! ==> defined new CTR 7 (PPA) 1793 197267 -775 001 <A 1113 011262 == Executing PA-CTR 2, V(1)=258, V(2)=2, repcount=87, factor=5/3 2924 543875 -1297 001 <A 111438 011 == Executing PPA-CTR 6 (once), V(1)=437 2933 549165 -1299 111 A> 110441 == Executing PA-CTR 3, V(1)=0, V(2)=437, repcount=146, factor=5/3 5269 1511889 15 111731 A> 1103 5270 1511890 14 111731 <A 1103 5271 1514083 -2179 <A 111731 1103 5272 1514086 -2178 011 C> 111731 1103 5273 1516279 15 011 111731 C> 1103 5274 1516282 18 011 111732 A> 1102 5275 1516283 17 011 111732 <A 1102 5276 1518479 -2179 011 <A 111732 1102 5277 1518482 -2182 <B 111733 1102 5278 1518483 -2181 001 C> 111733 1102 5279 1520682 18 001 111733 C> 1102 5280 1520685 21 001 111734 A> 110 5281 1520686 20 001 111734 <A 110 5282 1522888 -2182 001 <A 111734 110 5283 1522893 -2181 111 C> 111734 110 5284 1525095 21 111735 C> 110 5285 1525098 24 111736 A> 5286 1525099 23 111736 <B 100 5287 1527307 -2185 <B 101736 100 5288 1527308 -2184 001 C> 101736 100 5289 1527313 -2185 001 <A 111 101735 100 5290 1527318 -2184 111 C> 111 101735 100 5291 1527321 -2181 1112 C> 101735 100 5292 1527326 -2182 1112 <A 111 101734 100 5293 1527332 -2188 <A 1113 101734 100 >> Try to prove a PPA-CTR with 1 Vars... 0 0 0 1111+V(1) A> 1103 1 1 -1 1111+V(1) <A 1103 2 4+3*V(1) -4+-3*V(1) <A 1111+V(1) 1103 3 7+3*V(1) -3+-3*V(1) 011 C> 1111+V(1) 1103 4 10+6*V(1) 0 011 1111+V(1) C> 1103 5 13+6*V(1) 3 011 1112+V(1) A> 1102 6 14+6*V(1) 2 011 1112+V(1) <A 1102 7 20+9*V(1) -4+-3*V(1) 011 <A 1112+V(1) 1102 8 23+9*V(1) -7+-3*V(1) <B 1113+V(1) 1102 9 24+9*V(1) -6+-3*V(1) 001 C> 1113+V(1) 1102 10 33+12*V(1) 3 001 1113+V(1) C> 1102 11 36+12*V(1) 6 001 1114+V(1) A> 110 12 37+12*V(1) 5 001 1114+V(1) <A 110 13 49+15*V(1) -7+-3*V(1) 001 <A 1114+V(1) 110 14 54+15*V(1) -6+-3*V(1) 111 C> 1114+V(1) 110 15 66+18*V(1) 6 1115+V(1) C> 110 16 69+18*V(1) 9 1116+V(1) A> 17 70+18*V(1) 8 1116+V(1) <B 100 18 88+21*V(1) -10+-3*V(1) <B 1016+V(1) 100 19 89+21*V(1) -9+-3*V(1) 001 C> 1016+V(1) 100 20 94+21*V(1) -10+-3*V(1) 001 <A 111 1015+V(1) 100 21 99+21*V(1) -9+-3*V(1) 111 C> 111 1015+V(1) 100 22 102+21*V(1) -6+-3*V(1) 1112 C> 1015+V(1) 100 23 107+21*V(1) -7+-3*V(1) 1112 <A 111 1014+V(1) 100 24 113+21*V(1) -13+-3*V(1) <A 1113 1014+V(1) 100 << Success! ==> defined new CTR 8 (PPA) 5293 1527332 -2188 <A 1113 101734 100 == Executing PA-CTR 1, V(1)=730, V(2)=2, repcount=244, factor=5/3 8465 4223288 -3652 <A 1111223 1012 100 == Executing PPA-CTR 5 (once), V(1)=1222 8480 4245366 -3658 001 <A 111 0111227 == Executing PA-CTR 2, V(1)=1223, V(2)=0, repcount=408, factor=5/3 13784 11749710 -6106 001 <A 1112041 0113 13785 11749715 -6105 111 C> 1112041 0113 13786 11755838 18 1112042 C> 0113 13787 11755841 17 1112042 <A 111 0112 13788 11761967 -6109 <A 1112043 0112 13789 11761970 -6108 011 C> 1112043 0112 13790 11768099 21 011 1112043 C> 0112 13791 11768102 20 011 1112043 <A 111 011 13792 11774231 -6109 011 <A 1112044 011 13793 11774234 -6112 <B 1112045 011 13794 11774235 -6111 001 C> 1112045 011 13795 11780370 24 001 1112045 C> 011 13796 11780373 23 001 1112045 <A 111 13797 11786508 -6112 001 <A 1112046 13798 11786513 -6111 111 C> 1112046 13799 11792651 27 1112047 C> 13800 11792654 26 1112047 <D 110 13801 11798795 -6115 <D 1102048 13802 11798796 -6116 0 H> 01 1102048 [stop] Lines: 199 Top steps: 198 Macro steps: 13802 Basic steps: 11798796 Tape index: -6116 ones: 4097 log10(ones ): 3.612 log10(steps ): 7.072 Run state: stop
Input to awk program: gohalt 1 L 46 5T B1L A1L C1R D1L A1R C1R H1L E0L C1R B1L : 4097 11798796 T 5-state TM #4 from MaBu-List M 300 pref sim machv mbL5_4 just simple machv mbL5_4-r with repetitions reduced machv mbL5_4-1 with tape symbol exponents machv mbL5_4-m as 3-macro machine machv mbL5_4-a as 3-macro machine with pure additive config-TRs iam mbL5_4-a mtype 3 mmtyp 3 r 1 H 1 mac 0 E 2 sympr HM 1 date Tue Jul 6 22:10:19 CEST 2010 edate Tue Jul 6 22:10:20 CEST 2010 bnspeed 1Start: Tue Jul 6 22:10:19 CEST 2010
Constructed by: $Id: tmJob.awk,v 1.34 2010/05/06 18:26:17 heiner Exp $ $Id: basics.awk,v 1.1 2010/05/06 17:24:17 heiner Exp $ $Id: htSupp.awk,v 1.14 2010/07/06 19:48:32 heiner Exp $ $Id: mmSim.awk,v 1.34 2005/01/09 22:23:28 heiner Exp $ $Id: bignum.awk,v 1.34 2010/05/06 17:58:14 heiner Exp $ $Id: varLI.awk,v 1.11 2005/01/15 21:01:29 heiner Exp $ bignum signature: LEN={S++:9 U++:9 S+:8 U+:8 S*:4 U*:4} DONT: y i o;